Current through a 100Ω resistor at 3.3V

Worked answer for 3.3V applied across a 100Ω resistor, using Ohm's law (I = V/R) and power (P = V²/R).

Current 33.0 mA 3.3V ÷ 100Ω · dissipates 109 mW
Voltage (V)3.3 V
Resistance (R)100Ω
Current I = V / R33.0 mA
Power P = V² / R109 mW

Driving 3.3V through 100Ω gives 33.0 mA of current (I = V/R) and the resistor must dissipate 109 mW of heat (P = V²/R). Pick a resistor power rating comfortably above that figure.

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Disclaimer: This is a reference estimate using ideal Ohm's law. Real components have tolerance and self-heating; verify against your part's datasheet and power rating before building.

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