Current through a 2.2kΩ resistor at 24V
Worked answer for 24V applied across a 2.2kΩ resistor, using Ohm's law (I = V/R) and power (P = V²/R).
Current 10.9 mA 24V ÷ 2.2kΩ · dissipates 262 mW
| Voltage (V) | 24 V |
| Resistance (R) | 2.2kΩ |
| Current I = V / R | 10.9 mA |
| Power P = V² / R | 262 mW |
Driving 24V through 2.2kΩ gives 10.9 mA of current (I = V/R) and the resistor must dissipate 262 mW of heat (P = V²/R). Pick a resistor power rating comfortably above that figure.
Different values? Enter any two of voltage, current, resistance or power in the interactive tool:
Open the Ohm's Law Calculator →Disclaimer: This is a reference estimate using ideal Ohm's law. Real components have tolerance and self-heating; verify against your part's datasheet and power rating before building.