Current through a 10kΩ resistor at 12V
Worked answer for 12V applied across a 10kΩ resistor, using Ohm's law (I = V/R) and power (P = V²/R).
Current 1.2 mA 12V ÷ 10kΩ · dissipates 14.4 mW
| Voltage (V) | 12 V |
| Resistance (R) | 10kΩ |
| Current I = V / R | 1.2 mA |
| Power P = V² / R | 14.4 mW |
Driving 12V through 10kΩ gives 1.2 mA of current (I = V/R) and the resistor must dissipate 14.4 mW of heat (P = V²/R). Pick a resistor power rating comfortably above that figure.
Different values? Enter any two of voltage, current, resistance or power in the interactive tool:
Open the Ohm's Law Calculator →Disclaimer: This is a reference estimate using ideal Ohm's law. Real components have tolerance and self-heating; verify against your part's datasheet and power rating before building.